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Figure 10-3

This program produces this output:

.

Notice that two calls to the destructor are executed, but only one call is made to the constructor As the output illustrates, the constructor is not called when the copy of o (in main( )) is passed to ob (within f( )) The reason that the constructor is not called when the copy of the object is made is easy to understand When you pass an object to a function, you want the current state of that object If the constructor is called when the copy is created, initialization will occur, possibly changing the object Thus, the constructor cannot be executed when the copy of an object is generated in a function call Although the constructor is not called when an object is passed to a function, it is necessary to call the destructor when the copy is destroyed (The copy is destroyed like any other local variable, when the function terminates) Remember, the copy of the object does exist as long as the function is executing This means that the copy could be performing operations that will require a destructor to be called when the copy is destroyed For example, it is perfectly valid for the copy to allocate memory that must be freed when it is destroyed For this reason, the destructor must be executed when the copy is destroyed To summarize: When a copy of an object is generated because it is passed to a function, the object s constructor is not called However, when the copy of the object inside the function is destroyed, its destructor is called By default, when a copy of an object is made, a bitwise copy occurs This means that the new object is an exact duplicate of the original The fact that an exact copy is made can, at times, be a source of trouble Even though objects are passed to functions by means of the normal call-by-value parameter passing mechanism which, in theory, protects and insulates the calling argument, it is still possible for a side effect to occur that may affect, or even damage, the object used as an argument For example, if an object used as an argument allocates memory and frees that memory when it is destroyed, then its local copy inside the function will free the same memory when its destructor is called This will leave the original object damaged and effectively useless As you will see later in this book, it is possible to prevent this type of problem by defining the copy operation relative.

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A hands-free soap dispenser (Photo courtesy Smarthomecom)

to your own classes by creating a special type of constructor called a copy constructor (see 26)

The standard units of force are kg m/s2, also called a newton In step 1 of our problem we don t know the time over which the force is applied and we don t know the resulting velocity (that s what we re trying to calculate), so we re going to have to play with the above equations to get them into forms that contain what we do know We know the distance over which the force was applied (the 8-in, or 02-m, crouch), and we know the force and the mass which together can be used to calculate the acceleration Let s rearrange Eq (12-2) to put it in terms of what we want to calculate in step 1 v2 5 v1 1 at (12-4)

A function may return an object to the caller For example, this is a valid C++ program:

#include <iostream> using namespace std; class myclass { int i; public: void set_i(int n) { i=n; } int get_i() { return i; } }; myclass f(); int main() { myclass o; o = f(); cout << oget_i() << "\n"; return 0; } myclass f() { myclass x; xset_i(1); return x; } // return object of type myclass

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